View Code of Problem 72

#include <stdio.h>
int main()
{
	float m,sum=0.0;
	int n,i;
	float a[n+1];
	scanf("%f%d",&m,&n);
	a[0]=m;
	for(i=0;i<=n-1;i++)
	{
		a[i+1]=a[i]/2.0;
		
	}
	sum=m;
	for(i=1;i<=n-1;i++)
		sum=sum+a[i]*2;

	printf("%.2f %.2f\n",a[n],sum);
	return 0;
	 
}