View Code of Problem 42

#include<stdio.h>
#include<math.h>
main(){
	float a,b,c,m,n1,n2;
	scanf("%f%f%f",&a,&b,&c);
	m=b*b-4*a*c;
	n1=(-b+sqrt(m))/(2*a);
	n2=(-b-sqrt(m))/(2*a);
	printf("%.2f %.2f\n",n1,n2);
}

Double click to view unformatted code.


Back to problem 42