View Code of Problem 42

#include<stdio.h>
#include<math.h>
main(){
	int a,b,c;
	double x1,x2,y,z;
	scanf("%d%d%d",&a,&b,&c);
	if(sqrt(b*b-4*a*c)<=0)
		printf("无效输入\n");
	else{
		y=(-b+sqrt(b*b-4*a*c))/(2.0*a);
		z=(-b-sqrt(b*b-4*a*c))/(2.0*a);
		if(y>=z){
			x1=y;
			x2=z;
		}
		else{
			x1=z;
			x2=y;
		}
		printf("%.2f,%.2f\n",x1,x2);
	}
	return 0;
}