View Code of Problem 48

#include "stdio.h"

void main()
{
	int n;
	int i;
	int a[100],b[100];
	double sum=0,t;
	a[0]=1;a[1]=1;
	b[0]=0;b[1]=1;
	scanf("%d",&n);
	for(i=2;i<n+2;i++)
	{
		a[i]=a[i-1]+a[i-2];
		b[i]=b[i-1]+b[i-2];
		t=(a[i]/(b[i]*1.000000));
		sum=sum+t;	
	}
	printf("%.6lf",sum);
}